Base | Representation |
---|---|
bin | 1100000011000110001001… |
… | …1110100000100001000100 |
3 | 1201220102200021222122211012 |
4 | 3000301202132200201010 |
5 | 3214021013303234130 |
6 | 44101423500501352 |
7 | 2535042135122003 |
oct | 300614236404104 |
9 | 51812607878735 |
10 | 13247331305540 |
11 | 424818618a332 |
12 | 159b50854a858 |
13 | 7512aaba1b57 |
14 | 33b262232c3a |
15 | 17e8d8051995 |
hex | c0c627a0844 |
13247331305540 has 12 divisors (see below), whose sum is σ = 27819395741676. Its totient is φ = 5298932522208.
The previous prime is 13247331305497. The next prime is 13247331305573. The reversal of 13247331305540 is 4550313374231.
It can be written as a sum of positive squares in 2 ways, for example, as 6960236427076 + 6287094878464 = 2638226^2 + 2507408^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 331183282619 + ... + 331183282658.
It is an arithmetic number, because the mean of its divisors is an integer number (2318282978473).
Almost surely, 213247331305540 is an apocalyptic number.
13247331305540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13247331305540 is an abundant number, since it is smaller than the sum of its proper divisors (14572064436136).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13247331305540 is a wasteful number, since it uses less digits than its factorization.
13247331305540 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 662366565286 (or 662366565284 counting only the distinct ones).
The product of its (nonzero) digits is 453600, while the sum is 41.
Adding to 13247331305540 its reverse (4550313374231), we get a palindrome (17797644679771).
The spelling of 13247331305540 in words is "thirteen trillion, two hundred forty-seven billion, three hundred thirty-one million, three hundred five thousand, five hundred forty".
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