Base | Representation |
---|---|
bin | 1100000011010000010110… |
… | …1110010001100111001111 |
3 | 1201220200202011120002211020 |
4 | 3000310011232101213033 |
5 | 3214042120423000012 |
6 | 44102555335125223 |
7 | 2535200042525262 |
oct | 300640556214717 |
9 | 51820664502736 |
10 | 13250070125007 |
11 | 424936117a9a1 |
12 | 159bb51813813 |
13 | 75162642a9a1 |
14 | 33b441c8ccd9 |
15 | 17e9e8703a8c |
hex | c0d05b919cf |
13250070125007 has 4 divisors (see below), whose sum is σ = 17666760166680. Its totient is φ = 8833380083336.
The previous prime is 13250070124987. The next prime is 13250070125011. The reversal of 13250070125007 is 70052107005231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13250070125007 - 215 = 13250070092239 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13250070125027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2208345020832 + ... + 2208345020837.
It is an arithmetic number, because the mean of its divisors is an integer number (4416690041670).
Almost surely, 213250070125007 is an apocalyptic number.
13250070125007 is a deficient number, since it is larger than the sum of its proper divisors (4416690041673).
13250070125007 is an equidigital number, since it uses as much as digits as its factorization.
13250070125007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4416690041672.
The product of its (nonzero) digits is 14700, while the sum is 33.
The spelling of 13250070125007 in words is "thirteen trillion, two hundred fifty billion, seventy million, one hundred twenty-five thousand, seven".
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