Base | Representation |
---|---|
bin | 1100000011010000011110… |
… | …0000101010110001111011 |
3 | 1201220200211020222121221101 |
4 | 3000310013200222301323 |
5 | 3214042201112100012 |
6 | 44103002325552231 |
7 | 2535200555442346 |
oct | 300640740526173 |
9 | 51820736877841 |
10 | 13250100112507 |
11 | 42493770a1a55 |
12 | 159bb5b875677 |
13 | 75162c6ca07b |
14 | 33b445c5745d |
15 | 17e9eb178d57 |
hex | c0d0782ac7b |
13250100112507 has 2 divisors, whose sum is σ = 13250100112508. Its totient is φ = 13250100112506.
The previous prime is 13250100112493. The next prime is 13250100112541. The reversal of 13250100112507 is 70521100105231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13250100112507 - 215 = 13250100079739 is a prime.
It is not a weakly prime, because it can be changed into another prime (13250100112307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625050056253 + 6625050056254.
It is an arithmetic number, because the mean of its divisors is an integer number (6625050056254).
Almost surely, 213250100112507 is an apocalyptic number.
13250100112507 is a deficient number, since it is larger than the sum of its proper divisors (1).
13250100112507 is an equidigital number, since it uses as much as digits as its factorization.
13250100112507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2100, while the sum is 28.
Adding to 13250100112507 its reverse (70521100105231), we get a palindrome (83771200217738).
The spelling of 13250100112507 in words is "thirteen trillion, two hundred fifty billion, one hundred million, one hundred twelve thousand, five hundred seven".
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