Base | Representation |
---|---|
bin | 111101101100111000… |
… | …1000000011001100001 |
3 | 110200000022212111200010 |
4 | 1323121301000121201 |
5 | 4132331121141231 |
6 | 140512032515133 |
7 | 12400351564143 |
oct | 1733161003141 |
9 | 420008774603 |
10 | 132502521441 |
11 | 51215245574 |
12 | 2181a9abaa9 |
13 | c6584a7854 |
14 | 65ad9b4c93 |
15 | 36a78db546 |
hex | 1ed9c40661 |
132502521441 has 16 divisors (see below), whose sum is σ = 182533784576. Its totient is φ = 85443026256.
The previous prime is 132502521433. The next prime is 132502521457. The reversal of 132502521441 is 144125205231.
It is not a de Polignac number, because 132502521441 - 23 = 132502521433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132502521399 and 132502521408.
It is not an unprimeable number, because it can be changed into a prime (132502521421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4972885 + ... + 4999458.
It is an arithmetic number, because the mean of its divisors is an integer number (11408361536).
Almost surely, 2132502521441 is an apocalyptic number.
It is an amenable number.
132502521441 is a deficient number, since it is larger than the sum of its proper divisors (50031263135).
132502521441 is a wasteful number, since it uses less digits than its factorization.
132502521441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9972492.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 132502521441 its reverse (144125205231), we get a palindrome (276627726672).
The spelling of 132502521441 in words is "one hundred thirty-two billion, five hundred two million, five hundred twenty-one thousand, four hundred forty-one".
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