Base | Representation |
---|---|
bin | 1100000011010001101101… |
… | …1001000100110100110010 |
3 | 1201220201200111121220210120 |
4 | 3000310123121010310302 |
5 | 3214043342004310404 |
6 | 44103055403111110 |
7 | 2535212045551503 |
oct | 300643331046462 |
9 | 51821614556716 |
10 | 13250433666354 |
11 | 4249528403995 |
12 | 15a0033512496 |
13 | 751683845601 |
14 | 33b478282baa |
15 | 17ea1a5b49d9 |
hex | c0d1b644d32 |
13250433666354 has 32 divisors (see below), whose sum is σ = 26899053832896. Its totient is φ = 4350459801600.
The previous prime is 13250433666319. The next prime is 13250433666383. The reversal of 13250433666354 is 45366633405231.
It is a junction number, because it is equal to n+sod(n) for n = 13250433666297 and 13250433666306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2471754 + ... + 5710554.
It is an arithmetic number, because the mean of its divisors is an integer number (840595432278).
Almost surely, 213250433666354 is an apocalyptic number.
13250433666354 is an abundant number, since it is smaller than the sum of its proper divisors (13648620166542).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13250433666354 is a wasteful number, since it uses less digits than its factorization.
13250433666354 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3249050.
The product of its (nonzero) digits is 13996800, while the sum is 51.
The spelling of 13250433666354 in words is "thirteen trillion, two hundred fifty billion, four hundred thirty-three million, six hundred sixty-six thousand, three hundred fifty-four".
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