Base | Representation |
---|---|
bin | 111101101100111101… |
… | …0100011011011000001 |
3 | 110200000111120122210122 |
4 | 1323121322203123001 |
5 | 4132332241233233 |
6 | 140512202310025 |
7 | 12400412056613 |
oct | 1733172433301 |
9 | 420014518718 |
10 | 132505024193 |
11 | 512166a4963 |
12 | 2181b7b8315 |
13 | c658b72a79 |
14 | 65b0066db3 |
15 | 36a7c32d98 |
hex | 1ed9ea36c1 |
132505024193 has 2 divisors, whose sum is σ = 132505024194. Its totient is φ = 132505024192.
The previous prime is 132505024163. The next prime is 132505024199. The reversal of 132505024193 is 391420505231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132384639409 + 120384784 = 363847^2 + 10972^2 .
It is a cyclic number.
It is not a de Polignac number, because 132505024193 - 236 = 63785547457 is a prime.
It is not a weakly prime, because it can be changed into another prime (132505024199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66252512096 + 66252512097.
It is an arithmetic number, because the mean of its divisors is an integer number (66252512097).
Almost surely, 2132505024193 is an apocalyptic number.
It is an amenable number.
132505024193 is a deficient number, since it is larger than the sum of its proper divisors (1).
132505024193 is an equidigital number, since it uses as much as digits as its factorization.
132505024193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 132505024193 in words is "one hundred thirty-two billion, five hundred five million, twenty-four thousand, one hundred ninety-three".
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