Base | Representation |
---|---|
bin | 111101101101000111… |
… | …0000100111001011100 |
3 | 110200000212012200011200 |
4 | 1323122032010321130 |
5 | 4132340044021134 |
6 | 140512504115500 |
7 | 12400503423510 |
oct | 1733216047134 |
9 | 420025180150 |
10 | 132510142044 |
11 | 5121957aa95 |
12 | 21821465b90 |
13 | c659c45397 |
14 | 65b09da140 |
15 | 36a83e4499 |
hex | 1eda384e5c |
132510142044 has 72 divisors (see below), whose sum is σ = 392143865568. Its totient is φ = 36936622080.
The previous prime is 132510142031. The next prime is 132510142069. The reversal of 132510142044 is 440241015231.
132510142044 is a `hidden beast` number, since 1 + 3 + 2 + 510 + 142 + 0 + 4 + 4 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 132510141999 and 132510142017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6402277 + ... + 6422940.
Almost surely, 2132510142044 is an apocalyptic number.
132510142044 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
132510142044 is an abundant number, since it is smaller than the sum of its proper divisors (259633723524).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132510142044 is a wasteful number, since it uses less digits than its factorization.
132510142044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12825275 (or 12825270 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 27.
Adding to 132510142044 its reverse (440241015231), we get a palindrome (572751157275).
The spelling of 132510142044 in words is "one hundred thirty-two billion, five hundred ten million, one hundred forty-two thousand, forty-four".
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