Base | Representation |
---|---|
bin | 100111011111011… |
… | …1010011001011001 |
3 | 10102100102211000012 |
4 | 1032332322121121 |
5 | 10203212134334 |
6 | 335253451305 |
7 | 44560201643 |
oct | 11676723131 |
9 | 3370384005 |
10 | 1325114969 |
11 | 61aaa1542 |
12 | 30b940b35 |
13 | 1816bc5c9 |
14 | c7dbb893 |
15 | 7b5019ce |
hex | 4efba659 |
1325114969 has 2 divisors, whose sum is σ = 1325114970. Its totient is φ = 1325114968.
The previous prime is 1325114927. The next prime is 1325114977. The reversal of 1325114969 is 9694115231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 926593600 + 398521369 = 30440^2 + 19963^2 .
It is a cyclic number.
It is not a de Polignac number, because 1325114969 - 212 = 1325110873 is a prime.
It is a super-2 number, since 2×13251149692 = 3511859362135741922, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1325114909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662557484 + 662557485.
It is an arithmetic number, because the mean of its divisors is an integer number (662557485).
Almost surely, 21325114969 is an apocalyptic number.
It is an amenable number.
1325114969 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325114969 is an equidigital number, since it uses as much as digits as its factorization.
1325114969 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 58320, while the sum is 41.
The square root of 1325114969 is about 36402.1286328149. The cubic root of 1325114969 is about 1098.3763840372.
The spelling of 1325114969 in words is "one billion, three hundred twenty-five million, one hundred fourteen thousand, nine hundred sixty-nine".
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