Base | Representation |
---|---|
bin | 1100000011010111100000… |
… | …1110101010100100111011 |
3 | 1201220212201001102202122202 |
4 | 3000311320032222210323 |
5 | 3214110034222442431 |
6 | 44103514122540415 |
7 | 2535265460540024 |
oct | 300657016524473 |
9 | 51825631382582 |
10 | 13251991218491 |
11 | 424a157622963 |
12 | 15a03a906770b |
13 | 7518714385ac |
14 | 33b585087c4b |
15 | 17eaac1cb8cb |
hex | c0d783aa93b |
13251991218491 has 2 divisors, whose sum is σ = 13251991218492. Its totient is φ = 13251991218490.
The previous prime is 13251991218467. The next prime is 13251991218517. The reversal of 13251991218491 is 19481219915231.
13251991218491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (19481219915231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13251991218491 is a prime.
It is not a weakly prime, because it can be changed into another prime (13251991218461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625995609245 + 6625995609246.
It is an arithmetic number, because the mean of its divisors is an integer number (6625995609246).
Almost surely, 213251991218491 is an apocalyptic number.
13251991218491 is a deficient number, since it is larger than the sum of its proper divisors (1).
13251991218491 is an equidigital number, since it uses as much as digits as its factorization.
13251991218491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1399680, while the sum is 56.
The spelling of 13251991218491 in words is "thirteen trillion, two hundred fifty-one billion, nine hundred ninety-one million, two hundred eighteen thousand, four hundred ninety-one".
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