Base | Representation |
---|---|
bin | 11000101011110010… |
… | …01101100001001001 |
3 | 1021012120101120122001 |
4 | 30111321031201021 |
5 | 204120032033001 |
6 | 10031001031001 |
7 | 646255006555 |
oct | 142571154111 |
9 | 37176346561 |
10 | 13252221001 |
11 | 5690595868 |
12 | 269a185461 |
13 | 13327112b6 |
14 | 8da062865 |
15 | 528674001 |
hex | 315e4d849 |
13252221001 has 2 divisors, whose sum is σ = 13252221002. Its totient is φ = 13252221000.
The previous prime is 13252220963. The next prime is 13252221013. The reversal of 13252221001 is 10012225231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8869118976 + 4383102025 = 94176^2 + 66205^2 .
It is a cyclic number.
It is not a de Polignac number, because 13252221001 - 29 = 13252220489 is a prime.
It is a super-2 number, since 2×132522210012 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13252221001.
It is not a weakly prime, because it can be changed into another prime (13252221091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626110500 + 6626110501.
It is an arithmetic number, because the mean of its divisors is an integer number (6626110501).
Almost surely, 213252221001 is an apocalyptic number.
It is an amenable number.
13252221001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13252221001 is an equidigital number, since it uses as much as digits as its factorization.
13252221001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 19.
Adding to 13252221001 its reverse (10012225231), we get a palindrome (23264446232).
The spelling of 13252221001 in words is "thirteen billion, two hundred fifty-two million, two hundred twenty-one thousand, one".
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