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132522285475067 is a prime number
BaseRepresentation
bin11110001000011100111111…
…110000000010010011111011
3122101020000011221010021121212
4132020130333300002103323
5114332221120040200232
61145503521505153335
736625263526410545
oct3610347760022373
9571200157107555
10132522285475067
11392534273357a4
1212a4385932b84b
1358c3a4ac9ca57
1424a21818c4695
15104c31e8c7eb2
hex78873fc024fb

132522285475067 has 2 divisors, whose sum is σ = 132522285475068. Its totient is φ = 132522285475066.

The previous prime is 132522285474977. The next prime is 132522285475117. The reversal of 132522285475067 is 760574582225231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132522285475067 - 28 = 132522285474811 is a prime.

It is a super-2 number, since 2×1325222854750672 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132522285474997 and 132522285475015.

It is not a weakly prime, because it can be changed into another prime (132522285475667) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66261142737533 + 66261142737534.

It is an arithmetic number, because the mean of its divisors is an integer number (66261142737534).

Almost surely, 2132522285475067 is an apocalyptic number.

132522285475067 is a deficient number, since it is larger than the sum of its proper divisors (1).

132522285475067 is an equidigital number, since it uses as much as digits as its factorization.

132522285475067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56448000, while the sum is 59.

The spelling of 132522285475067 in words is "one hundred thirty-two trillion, five hundred twenty-two billion, two hundred eighty-five million, four hundred seventy-five thousand, sixty-seven".