Base | Representation |
---|---|
bin | 11110001000011100111111… |
… | …110000000010011100010011 |
3 | 122101020000011221010022100201 |
4 | 132020130333300002130103 |
5 | 114332221120040204403 |
6 | 1145503521505200031 |
7 | 36625263526412242 |
oct | 3610347760023423 |
9 | 571200157108321 |
10 | 132522285475603 |
11 | 39253427336141 |
12 | 12a43859330017 |
13 | 58c3a4aca007a |
14 | 24a21818c4959 |
15 | 104c31e8c821d |
hex | 78873fc02713 |
132522285475603 has 2 divisors, whose sum is σ = 132522285475604. Its totient is φ = 132522285475602.
The previous prime is 132522285475507. The next prime is 132522285475667. The reversal of 132522285475603 is 306574582225231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132522285475603 - 217 = 132522285344531 is a prime.
It is a super-2 number, since 2×1325222854756032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132522285475673) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66261142737801 + 66261142737802.
It is an arithmetic number, because the mean of its divisors is an integer number (66261142737802).
Almost surely, 2132522285475603 is an apocalyptic number.
132522285475603 is a deficient number, since it is larger than the sum of its proper divisors (1).
132522285475603 is an equidigital number, since it uses as much as digits as its factorization.
132522285475603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192000, while the sum is 55.
The spelling of 132522285475603 in words is "one hundred thirty-two trillion, five hundred twenty-two billion, two hundred eighty-five million, four hundred seventy-five thousand, six hundred three".
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