Base | Representation |
---|---|
bin | 11000101011110010… |
… | …10101101110111001 |
3 | 1021012120110021210021 |
4 | 30111321111232321 |
5 | 204120034122044 |
6 | 10031001450441 |
7 | 646255206634 |
oct | 142571255671 |
9 | 37176407707 |
10 | 13252254649 |
11 | 5690609077 |
12 | 269a1a0a21 |
13 | 13327236ca |
14 | 8da070c1b |
15 | 52867de84 |
hex | 315e55bb9 |
13252254649 has 2 divisors, whose sum is σ = 13252254650. Its totient is φ = 13252254648.
The previous prime is 13252254623. The next prime is 13252254683. The reversal of 13252254649 is 94645225231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6730561600 + 6521693049 = 82040^2 + 80757^2 .
It is an emirp because it is prime and its reverse (94645225231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13252254649 - 213 = 13252246457 is a prime.
It is a super-2 number, since 2×132522546492 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13252255649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626127324 + 6626127325.
It is an arithmetic number, because the mean of its divisors is an integer number (6626127325).
Almost surely, 213252254649 is an apocalyptic number.
It is an amenable number.
13252254649 is a deficient number, since it is larger than the sum of its proper divisors (1).
13252254649 is an equidigital number, since it uses as much as digits as its factorization.
13252254649 is an evil number, because the sum of its binary digits is even.
The product of its digits is 518400, while the sum is 43.
The spelling of 13252254649 in words is "thirteen billion, two hundred fifty-two million, two hundred fifty-four thousand, six hundred forty-nine".
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