Base | Representation |
---|---|
bin | 10011010010001110100… |
… | …110101011100000111111 |
3 | 11200200200102102211121102 |
4 | 103102032212223200333 |
5 | 133203044030302201 |
6 | 2452450304323315 |
7 | 164513512543313 |
oct | 23221646534077 |
9 | 4620612384542 |
10 | 1325242431551 |
11 | 471039892675 |
12 | 194a1101353b |
13 | 97c7b92347c |
14 | 481dbbdbb43 |
15 | 2471503426b |
hex | 1348e9ab83f |
1325242431551 has 4 divisors (see below), whose sum is σ = 1326092492400. Its totient is φ = 1324392370704.
The previous prime is 1325242431479. The next prime is 1325242431563. The reversal of 1325242431551 is 1551342425231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1325242431551 - 226 = 1325175322687 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1325242431571) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425028086 + ... + 425031203.
It is an arithmetic number, because the mean of its divisors is an integer number (331523123100).
Almost surely, 21325242431551 is an apocalyptic number.
1325242431551 is a deficient number, since it is larger than the sum of its proper divisors (850060849).
1325242431551 is an equidigital number, since it uses as much as digits as its factorization.
1325242431551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 850060848.
The product of its digits is 144000, while the sum is 38.
Adding to 1325242431551 its reverse (1551342425231), we get a palindrome (2876584856782).
The spelling of 1325242431551 in words is "one trillion, three hundred twenty-five billion, two hundred forty-two million, four hundred thirty-one thousand, five hundred fifty-one".
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