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132524252034 = 231091407114401
BaseRepresentation
bin111101101101100001…
…1111001101110000010
3110200001211202112102220
41323123003321232002
54132402202031114
6140514130351510
712401034361506
oct1733303715602
9420054675386
10132524252034
1151226538039
122182612b596
13c65cb458a5
1465b2830306
1536a97800a9
hex1edb0f9b82

132524252034 has 32 divisors (see below), whose sum is σ = 267517726080. Its totient is φ = 43763328000.

The previous prime is 132524252009. The next prime is 132524252041. The reversal of 132524252034 is 430252425231.

132524252034 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 132524251986 and 132524252004.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9195234 + ... + 9209634.

It is an arithmetic number, because the mean of its divisors is an integer number (8359928940).

Almost surely, 2132524252034 is an apocalyptic number.

132524252034 is an abundant number, since it is smaller than the sum of its proper divisors (134993474046).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132524252034 is a wasteful number, since it uses less digits than its factorization.

132524252034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28586.

The product of its (nonzero) digits is 57600, while the sum is 33.

Adding to 132524252034 its reverse (430252425231), we get a palindrome (562776677265).

The spelling of 132524252034 in words is "one hundred thirty-two billion, five hundred twenty-four million, two hundred fifty-two thousand, thirty-four".

Divisors: 1 2 3 6 109 218 327 654 14071 14401 28142 28802 42213 43203 84426 86406 1533739 1569709 3067478 3139418 4601217 4709127 9202434 9418254 202636471 405272942 607909413 1215818826 22087375339 44174750678 66262126017 132524252034