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132531252137 is a prime number
BaseRepresentation
bin111101101101101111…
…0100110101110101001
3110200002022221011202222
41323123132212232221
54132411000032022
6140514540403425
712401151025124
oct1733336465651
9420068834688
10132531252137
115122a489349
1221828546575
13c661426b6b
1465b37333bb
1536aa1b4242
hex1edb7a6ba9

132531252137 has 2 divisors, whose sum is σ = 132531252138. Its totient is φ = 132531252136.

The previous prime is 132531252043. The next prime is 132531252151. The reversal of 132531252137 is 731252135231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120809075776 + 11722176361 = 347576^2 + 108269^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132531252137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132531252097 and 132531252106.

It is not a weakly prime, because it can be changed into another prime (132531252037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66265626068 + 66265626069.

It is an arithmetic number, because the mean of its divisors is an integer number (66265626069).

Almost surely, 2132531252137 is an apocalyptic number.

It is an amenable number.

132531252137 is a deficient number, since it is larger than the sum of its proper divisors (1).

132531252137 is an equidigital number, since it uses as much as digits as its factorization.

132531252137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 37800, while the sum is 35.

Adding to 132531252137 its reverse (731252135231), we get a palindrome (863783387368).

The spelling of 132531252137 in words is "one hundred thirty-two billion, five hundred thirty-one million, two hundred fifty-two thousand, one hundred thirty-seven".