Base | Representation |
---|---|
bin | 111101101101101111… |
… | …0100110101110101001 |
3 | 110200002022221011202222 |
4 | 1323123132212232221 |
5 | 4132411000032022 |
6 | 140514540403425 |
7 | 12401151025124 |
oct | 1733336465651 |
9 | 420068834688 |
10 | 132531252137 |
11 | 5122a489349 |
12 | 21828546575 |
13 | c661426b6b |
14 | 65b37333bb |
15 | 36aa1b4242 |
hex | 1edb7a6ba9 |
132531252137 has 2 divisors, whose sum is σ = 132531252138. Its totient is φ = 132531252136.
The previous prime is 132531252043. The next prime is 132531252151. The reversal of 132531252137 is 731252135231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 120809075776 + 11722176361 = 347576^2 + 108269^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132531252137 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132531252097 and 132531252106.
It is not a weakly prime, because it can be changed into another prime (132531252037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66265626068 + 66265626069.
It is an arithmetic number, because the mean of its divisors is an integer number (66265626069).
Almost surely, 2132531252137 is an apocalyptic number.
It is an amenable number.
132531252137 is a deficient number, since it is larger than the sum of its proper divisors (1).
132531252137 is an equidigital number, since it uses as much as digits as its factorization.
132531252137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 37800, while the sum is 35.
Adding to 132531252137 its reverse (731252135231), we get a palindrome (863783387368).
The spelling of 132531252137 in words is "one hundred thirty-two billion, five hundred thirty-one million, two hundred fifty-two thousand, one hundred thirty-seven".
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