Base | Representation |
---|---|
bin | 11000101011111011… |
… | …00001101001101011 |
3 | 1021012122112001010111 |
4 | 30111331201221223 |
5 | 204120324231133 |
6 | 10031041155151 |
7 | 646300430221 |
oct | 142575415153 |
9 | 37178461114 |
10 | 13253352043 |
11 | 5691198608 |
12 | 269a62bab7 |
13 | 1332a19059 |
14 | 8da278b11 |
15 | 5287e91cd |
hex | 315f61a6b |
13253352043 has 2 divisors, whose sum is σ = 13253352044. Its totient is φ = 13253352042.
The previous prime is 13253352029. The next prime is 13253352059. The reversal of 13253352043 is 34025335231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13253352043 - 217 = 13253220971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13253351996 and 13253352014.
It is not a weakly prime, because it can be changed into another prime (13253352443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6626676021 + 6626676022.
It is an arithmetic number, because the mean of its divisors is an integer number (6626676022).
Almost surely, 213253352043 is an apocalyptic number.
13253352043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13253352043 is an equidigital number, since it uses as much as digits as its factorization.
13253352043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 31.
Adding to 13253352043 its reverse (34025335231), we get a palindrome (47278687274).
The spelling of 13253352043 in words is "thirteen billion, two hundred fifty-three million, three hundred fifty-two thousand, forty-three".
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