Base | Representation |
---|---|
bin | 11110001000101000001000… |
… | …100011000000010101101010 |
3 | 122101021011001100121011121011 |
4 | 132020220020203000111222 |
5 | 114332420113004322442 |
6 | 1145513220302334134 |
7 | 36626166060125152 |
oct | 3610501043002552 |
9 | 571234040534534 |
10 | 132534244214122 |
11 | 39258503775413 |
12 | 12a4603628a34a |
13 | 58c4c05718aca |
14 | 24a2997c41762 |
15 | 104c7be6e8117 |
hex | 788a088c056a |
132534244214122 has 4 divisors (see below), whose sum is σ = 198801366321186. Its totient is φ = 66267122107060.
The previous prime is 132534244214101. The next prime is 132534244214123. The reversal of 132534244214122 is 221412442435231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 76299858130441 + 56234386083681 = 8734979^2 + 7498959^2 .
It is not an unprimeable number, because it can be changed into a prime (132534244214123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33133561053529 + ... + 33133561053532.
Almost surely, 2132534244214122 is an apocalyptic number.
132534244214122 is a deficient number, since it is larger than the sum of its proper divisors (66267122107064).
132534244214122 is an equidigital number, since it uses as much as digits as its factorization.
132534244214122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66267122107063.
The product of its digits is 368640, while the sum is 40.
Adding to 132534244214122 its reverse (221412442435231), we get a palindrome (353946686649353).
The spelling of 132534244214122 in words is "one hundred thirty-two trillion, five hundred thirty-four billion, two hundred forty-four million, two hundred fourteen thousand, one hundred twenty-two".
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