Base | Representation |
---|---|
bin | 100111011111111… |
… | …0100010001000000 |
3 | 10102100212212011010 |
4 | 1032333310101000 |
5 | 10203242231000 |
6 | 335302520520 |
7 | 44562210000 |
oct | 11677642100 |
9 | 3370785133 |
10 | 1325352000 |
11 | 620143635 |
12 | 30ba36140 |
13 | 18177346b |
14 | c8040000 |
15 | 7b54bd50 |
hex | 4eff4440 |
1325352000 has 560 divisors, whose sum is σ = 5327367552. Its totient is φ = 289766400.
The previous prime is 1325351999. The next prime is 1325352001. The reversal of 1325352000 is 2535231.
It is an interprime number because it is at equal distance from previous prime (1325351999) and next prime (1325352001).
It is a tau number, because it is divible by the number of its divisors (560).
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (1325352001) by changing a digit.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 57623989 + ... + 57624011.
Almost surely, 21325352000 is an apocalyptic number.
1325352000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1325352000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2663683776).
1325352000 is an abundant number, since it is smaller than the sum of its proper divisors (4002015552).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1325352000 is an frugal number, since it uses more digits than its factorization.
1325352000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81 (or 40 counting only the distinct ones).
The product of its (nonzero) digits is 900, while the sum is 21.
The square root of 1325352000 is about 36405.3842171732. The cubic root of 1325352000 is about 1098.4418711174.
Adding to 1325352000 its reverse (2535231), we get a palindrome (1327887231).
The spelling of 1325352000 in words is "one billion, three hundred twenty-five million, three hundred fifty-two thousand".
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