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132536993 is a prime number
BaseRepresentation
bin1111110011001…
…01101010100001
3100020101120120112
413321211222201
5232412140433
621052421105
73166355141
oct771455241
9306346515
10132536993
11688a5006
1238477795
13215c6474
1413860921
15b980348
hex7e65aa1

132536993 has 2 divisors, whose sum is σ = 132536994. Its totient is φ = 132536992.

The previous prime is 132536953. The next prime is 132537007. The reversal of 132536993 is 399635231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66716224 + 65820769 = 8168^2 + 8113^2 .

It is an emirp because it is prime and its reverse (399635231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132536993 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 132536993.

It is not a weakly prime, because it can be changed into another prime (132536903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66268496 + 66268497.

It is an arithmetic number, because the mean of its divisors is an integer number (66268497).

Almost surely, 2132536993 is an apocalyptic number.

It is an amenable number.

132536993 is a deficient number, since it is larger than the sum of its proper divisors (1).

132536993 is an equidigital number, since it uses as much as digits as its factorization.

132536993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 131220, while the sum is 41.

The square root of 132536993 is about 11512.4711943179. The cubic root of 132536993 is about 509.8538514972.

The spelling of 132536993 in words is "one hundred thirty-two million, five hundred thirty-six thousand, nine hundred ninety-three".