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13254015114120 = 233511411341718253
BaseRepresentation
bin1100000011011111000011…
…0111001101101110001000
31201221001221002202022112010
43000313300313031232020
53214123210332122440
644104451022015520
72535366564424254
oct300676067155610
951831832668463
1013254015114120
11424aaa6000680
1215a0872a175a0
13751b0482b281
1433b6d7ba3264
1517eb79c0e580
hexc0df0dcdb88

13254015114120 has 256 divisors, whose sum is σ = 44440493287680. Its totient is φ = 3134321049600.

The previous prime is 13254015114101. The next prime is 13254015114127. The reversal of 13254015114120 is 2141151045231.

13254015114120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is not an unprimeable number, because it can be changed into a prime (13254015114127) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 726118914 + ... + 726137166.

It is an arithmetic number, because the mean of its divisors is an integer number (173595676905).

Almost surely, 213254015114120 is an apocalyptic number.

13254015114120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13254015114120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22220246643840).

13254015114120 is an abundant number, since it is smaller than the sum of its proper divisors (31186478173560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13254015114120 is a wasteful number, since it uses less digits than its factorization.

13254015114120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31736 (or 31732 counting only the distinct ones).

The product of its (nonzero) digits is 4800, while the sum is 30.

Adding to 13254015114120 its reverse (2141151045231), we get a palindrome (15395166159351).

The spelling of 13254015114120 in words is "thirteen trillion, two hundred fifty-four billion, fifteen million, one hundred fourteen thousand, one hundred twenty".