Base | Representation |
---|---|
bin | 1111110011001… |
… | …10100010000011 |
3 | 100020101202110011 |
4 | 13321212202003 |
5 | 232412244142 |
6 | 21052445351 |
7 | 3166401406 |
oct | 771464203 |
9 | 306352404 |
10 | 132540547 |
11 | 688a7747 |
12 | 38479857 |
13 | 215c7c79 |
14 | 13861d3d |
15 | b981417 |
hex | 7e66883 |
132540547 has 2 divisors, whose sum is σ = 132540548. Its totient is φ = 132540546.
The previous prime is 132540521. The next prime is 132540563. The reversal of 132540547 is 745045231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132540547 - 215 = 132507779 is a prime.
It is not a weakly prime, because it can be changed into another prime (132540587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66270273 + 66270274.
It is an arithmetic number, because the mean of its divisors is an integer number (66270274).
Almost surely, 2132540547 is an apocalyptic number.
132540547 is a deficient number, since it is larger than the sum of its proper divisors (1).
132540547 is an equidigital number, since it uses as much as digits as its factorization.
132540547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 31.
The square root of 132540547 is about 11512.6255476325. The cubic root of 132540547 is about 509.8584087265.
Adding to 132540547 its reverse (745045231), we get a palindrome (877585778).
The spelling of 132540547 in words is "one hundred thirty-two million, five hundred forty thousand, five hundred forty-seven".
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