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132540641 is a prime number
BaseRepresentation
bin1111110011001…
…10100011100001
3100020101202120122
413321212203201
5232412300031
621052450025
73166401602
oct771464341
9306352518
10132540641
11688a7822
1238479915
13215c801c
1413861da9
15b98147b
hex7e668e1

132540641 has 2 divisors, whose sum is σ = 132540642. Its totient is φ = 132540640.

The previous prime is 132540631. The next prime is 132540649. The reversal of 132540641 is 146045231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106172416 + 26368225 = 10304^2 + 5135^2 .

It is an emirp because it is prime and its reverse (146045231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132540641 - 214 = 132524257 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132540641.

It is not a weakly prime, because it can be changed into another prime (132540649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66270320 + 66270321.

It is an arithmetic number, because the mean of its divisors is an integer number (66270321).

Almost surely, 2132540641 is an apocalyptic number.

It is an amenable number.

132540641 is a deficient number, since it is larger than the sum of its proper divisors (1).

132540641 is an equidigital number, since it uses as much as digits as its factorization.

132540641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 26.

The square root of 132540641 is about 11512.6296301062. The cubic root of 132540641 is about 509.8585292598.

Adding to 132540641 its reverse (146045231), we get a palindrome (278585872).

The spelling of 132540641 in words is "one hundred thirty-two million, five hundred forty thousand, six hundred forty-one".