Base | Representation |
---|---|
bin | 10011010010011010000… |
… | …010011000110110110011 |
3 | 11200201011210100221112212 |
4 | 103102122002120312303 |
5 | 133203442131311111 |
6 | 2452521315442335 |
7 | 164521332121655 |
oct | 23223202306663 |
9 | 4621153327485 |
10 | 1325434244531 |
11 | 4711280935a1 |
12 | 194a652b63ab |
13 | 97cac5a2187 |
14 | 4821948c6d5 |
15 | 24726cc298b |
hex | 1349a098db3 |
1325434244531 has 2 divisors, whose sum is σ = 1325434244532. Its totient is φ = 1325434244530.
The previous prime is 1325434244507. The next prime is 1325434244549. The reversal of 1325434244531 is 1354424345231.
It is a strong prime.
It is an emirp because it is prime and its reverse (1354424345231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1325434244531 is a prime.
It is a super-2 number, since 2×13254342445312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1325434243531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662717122265 + 662717122266.
It is an arithmetic number, because the mean of its divisors is an integer number (662717122266).
Almost surely, 21325434244531 is an apocalyptic number.
1325434244531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325434244531 is an equidigital number, since it uses as much as digits as its factorization.
1325434244531 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 691200, while the sum is 41.
Adding to 1325434244531 its reverse (1354424345231), we get a palindrome (2679858589762).
The spelling of 1325434244531 in words is "one trillion, three hundred twenty-five billion, four hundred thirty-four million, two hundred forty-four thousand, five hundred thirty-one".
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