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13254541103 = 26949273387
BaseRepresentation
bin11000101100000100…
…00011111100101111
31021012201202110012202
430112002003330233
5204121130303403
610031122452115
7646313511656
oct142602037457
937181673182
1013254541103
11569192aa01
12269ab0403b
13133304433b
148da4a819d
15528981688
hex316083f2f

13254541103 has 4 divisors (see below), whose sum is σ = 13303814760. Its totient is φ = 13205267448.

The previous prime is 13254541081. The next prime is 13254541121. The reversal of 13254541103 is 30114545231.

13254541103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13254541103 - 212 = 13254537007 is a prime.

It is a super-2 number, since 2×132545411032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13254541163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24636425 + ... + 24636962.

It is an arithmetic number, because the mean of its divisors is an integer number (3325953690).

Almost surely, 213254541103 is an apocalyptic number.

13254541103 is a deficient number, since it is larger than the sum of its proper divisors (49273657).

13254541103 is an equidigital number, since it uses as much as digits as its factorization.

13254541103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49273656.

The product of its (nonzero) digits is 7200, while the sum is 29.

The spelling of 13254541103 in words is "thirteen billion, two hundred fifty-four million, five hundred forty-one thousand, one hundred three".

Divisors: 1 269 49273387 13254541103