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132550445042111 = 577229723474943
BaseRepresentation
bin11110001000110111001110…
…001100010000100110111111
3122101022200212102022111121102
4132020313032030100212333
5114333201302412321421
61145524500034323315
736630311410651625
oct3610671614204677
9571280772274542
10132550445042111
1139264367709258
1212a491b7a2953b
1358c65b7c89165
1424a369372d515
15104ce1bb5d60b
hex788dce3109bf

132550445042111 has 4 divisors (see below), whose sum is σ = 132780168517632. Its totient is φ = 132320721566592.

The previous prime is 132550445042063. The next prime is 132550445042129. The reversal of 132550445042111 is 111240544055231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132550445042111 - 234 = 132533265172927 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132550445042131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114861736895 + ... + 114861738048.

It is an arithmetic number, because the mean of its divisors is an integer number (33195042129408).

Almost surely, 2132550445042111 is an apocalyptic number.

132550445042111 is a deficient number, since it is larger than the sum of its proper divisors (229723475521).

132550445042111 is an equidigital number, since it uses as much as digits as its factorization.

132550445042111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 229723475520.

The product of its (nonzero) digits is 96000, while the sum is 38.

Adding to 132550445042111 its reverse (111240544055231), we get a palindrome (243790989097342).

The spelling of 132550445042111 in words is "one hundred thirty-two trillion, five hundred fifty billion, four hundred forty-five million, forty-two thousand, one hundred eleven".

Divisors: 1 577 229723474943 132550445042111