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132551324666045 = 526510264933209
BaseRepresentation
bin11110001000111000000010…
…100111110000100010111101
3122101022210010201111000210122
4132020320002213300202331
5114333210103103303140
61145525123215544325
736630342251434115
oct3610700247604275
9571283121430718
10132551324666045
113926477919378a
1212a4940252b0a5
1358c66c829a1ac
1424a37384a4045
15104ce6deb2ab5
hex788e029f08bd

132551324666045 has 4 divisors (see below), whose sum is σ = 159061589599260. Its totient is φ = 106041059732832.

The previous prime is 132551324665993. The next prime is 132551324666083. The reversal of 132551324666045 is 540666423155231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 104777866043236 + 27773458622809 = 10236106^2 + 5270053^2 .

It is a cyclic number.

It is not a de Polignac number, because 132551324666045 - 224 = 132551307888829 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13255132466600 + ... + 13255132466609.

It is an arithmetic number, because the mean of its divisors is an integer number (39765397399815).

Almost surely, 2132551324666045 is an apocalyptic number.

It is an amenable number.

132551324666045 is a deficient number, since it is larger than the sum of its proper divisors (26510264933215).

132551324666045 is an equidigital number, since it uses as much as digits as its factorization.

132551324666045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26510264933214.

The product of its (nonzero) digits is 15552000, while the sum is 53.

The spelling of 132551324666045 in words is "one hundred thirty-two trillion, five hundred fifty-one billion, three hundred twenty-four million, six hundred sixty-six thousand, forty-five".

Divisors: 1 5 26510264933209 132551324666045