Base | Representation |
---|---|
bin | 111101101110010110… |
… | …1110000100000001111 |
3 | 110200010202222100121210 |
4 | 1323130231300200033 |
5 | 4132431303022201 |
6 | 140521001225503 |
7 | 12401522265054 |
oct | 1733455604017 |
9 | 420122870553 |
10 | 132552001551 |
11 | 51240170722 |
12 | 21833492293 |
13 | c665810418 |
14 | 65b63b502b |
15 | 36abe121d6 |
hex | 1edcb7080f |
132552001551 has 16 divisors (see below), whose sum is σ = 177452329824. Its totient is φ = 88009949184.
The previous prime is 132552001513. The next prime is 132552001553. The reversal of 132552001551 is 155100255231.
It is not a de Polignac number, because 132552001551 - 29 = 132552001039 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132552001553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7189621 + ... + 7208033.
It is an arithmetic number, because the mean of its divisors is an integer number (11090770614).
Almost surely, 2132552001551 is an apocalyptic number.
132552001551 is a deficient number, since it is larger than the sum of its proper divisors (44900328273).
132552001551 is a wasteful number, since it uses less digits than its factorization.
132552001551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28010.
The product of its (nonzero) digits is 7500, while the sum is 30.
Adding to 132552001551 its reverse (155100255231), we get a palindrome (287652256782).
The spelling of 132552001551 in words is "one hundred thirty-two billion, five hundred fifty-two million, one thousand, five hundred fifty-one".
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