Base | Representation |
---|---|
bin | 11110001000111001111001… |
… | …000110111010001100110111 |
3 | 122101022222021021000200002011 |
4 | 132020321321012322030313 |
5 | 114333223141002343133 |
6 | 1145530052351025051 |
7 | 36630442440216253 |
oct | 3610717106721467 |
9 | 571288237020064 |
10 | 132553312543543 |
11 | 392655a9300551 |
12 | 12a4987820b187 |
13 | 58c695408b878 |
14 | 24a38864c5263 |
15 | 104d03877d6cd |
hex | 788e791ba337 |
132553312543543 has 4 divisors (see below), whose sum is σ = 134042675605920. Its totient is φ = 131063949481168.
The previous prime is 132553312543517. The next prime is 132553312543571. The reversal of 132553312543543 is 345345213355231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132553312543543 - 29 = 132553312543031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132553312543243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 744681531055 + ... + 744681531232.
It is an arithmetic number, because the mean of its divisors is an integer number (33510668901480).
Almost surely, 2132553312543543 is an apocalyptic number.
132553312543543 is a deficient number, since it is larger than the sum of its proper divisors (1489363062377).
132553312543543 is an equidigital number, since it uses as much as digits as its factorization.
132553312543543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1489363062376.
The product of its digits is 9720000, while the sum is 49.
Adding to 132553312543543 its reverse (345345213355231), we get a palindrome (477898525898774).
The spelling of 132553312543543 in words is "one hundred thirty-two trillion, five hundred fifty-three billion, three hundred twelve million, five hundred forty-three thousand, five hundred forty-three".
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