Base | Representation |
---|---|
bin | 11110001000111001111001… |
… | …000110111010001100110110 |
3 | 122101022222021021000200002010 |
4 | 132020321321012322030312 |
5 | 114333223141002343132 |
6 | 1145530052351025050 |
7 | 36630442440216252 |
oct | 3610717106721466 |
9 | 571288237020063 |
10 | 132553312543542 |
11 | 392655a9300550 |
12 | 12a4987820b186 |
13 | 58c695408b877 |
14 | 24a38864c5262 |
15 | 104d03877d6cc |
hex | 788e791ba336 |
132553312543542 has 64 divisors (see below), whose sum is σ = 290127169177344. Its totient is φ = 40039907437440.
The previous prime is 132553312543517. The next prime is 132553312543571. The reversal of 132553312543542 is 245345213355231.
It is a junction number, because it is equal to n+sod(n) for n = 132553312543491 and 132553312543500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1235955373 + ... + 1236062615.
It is an arithmetic number, because the mean of its divisors is an integer number (4533237018396).
Almost surely, 2132553312543542 is an apocalyptic number.
132553312543542 is an abundant number, since it is smaller than the sum of its proper divisors (157573856633802).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132553312543542 is a wasteful number, since it uses less digits than its factorization.
132553312543542 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 166653.
The product of its digits is 6480000, while the sum is 48.
Adding to 132553312543542 its reverse (245345213355231), we get a palindrome (377898525898773).
The spelling of 132553312543542 in words is "one hundred thirty-two trillion, five hundred fifty-three billion, three hundred twelve million, five hundred forty-three thousand, five hundred forty-two".
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