Base | Representation |
---|---|
bin | 11000101100001010… |
… | …11110000100110011 |
3 | 1021012210102211210021 |
4 | 30112011132010303 |
5 | 204121342401142 |
6 | 10031153544311 |
7 | 646324222525 |
oct | 142605360463 |
9 | 37183384707 |
10 | 13255434547 |
11 | 5692390193 |
12 | 269b275097 |
13 | 1333297bc4 |
14 | 8da65ba15 |
15 | 528aab267 |
hex | 31615e133 |
13255434547 has 2 divisors, whose sum is σ = 13255434548. Its totient is φ = 13255434546.
The previous prime is 13255434481. The next prime is 13255434583. The reversal of 13255434547 is 74543455231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13255434547 - 211 = 13255432499 is a prime.
It is not a weakly prime, because it can be changed into another prime (13255434587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6627717273 + 6627717274.
It is an arithmetic number, because the mean of its divisors is an integer number (6627717274).
Almost surely, 213255434547 is an apocalyptic number.
13255434547 is a deficient number, since it is larger than the sum of its proper divisors (1).
13255434547 is an equidigital number, since it uses as much as digits as its factorization.
13255434547 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1008000, while the sum is 43.
Adding to 13255434547 its reverse (74543455231), we get a palindrome (87798889778).
The spelling of 13255434547 in words is "thirteen billion, two hundred fifty-five million, four hundred thirty-four thousand, five hundred forty-seven".
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