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13256440331 = 131827122363
BaseRepresentation
bin11000101100010010…
…10011101000001011
31021012212022221110112
430112021103220023
5204122122042311
610031231304535
7646335612041
oct142611235013
937185287415
1013256440331
115692a07912
12269b67b14b
13133355a944
148da840391
15528c0928b
hex316253a0b

13256440331 has 8 divisors (see below), whose sum is σ = 13373895744. Its totient is φ = 13139231560.

The previous prime is 13256440297. The next prime is 13256440339. The reversal of 13256440331 is 13304465231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13256440331 is a prime.

It is a super-2 number, since 2×132564403312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13256440339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47156 + ... + 169518.

It is an arithmetic number, because the mean of its divisors is an integer number (1671736968).

Almost surely, 213256440331 is an apocalyptic number.

13256440331 is a deficient number, since it is larger than the sum of its proper divisors (117455413).

13256440331 is a wasteful number, since it uses less digits than its factorization.

13256440331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123321.

The product of its (nonzero) digits is 25920, while the sum is 32.

Subtracting 13256440331 from its reverse (13304465231), we obtain a triangular number (48024900 = T9800).

The spelling of 13256440331 in words is "thirteen billion, two hundred fifty-six million, four hundred forty thousand, three hundred thirty-one".

Divisors: 1 131 827 108337 122363 16029553 101194201 13256440331