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132603135234046 = 266301567617023
BaseRepresentation
bin11110001001101000010010…
…110001011000111111111110
3122101111201212111012120210121
4132021220102301120333332
5114340032210104442141
61150005012300125154
736634155210130561
oct3611502261307776
9571451774176717
10132603135234046
1139284745979324
1212a574618367ba
1358cb56418a219
1424a605145c4d8
15104e4a279c1d1
hex789a12c58ffe

132603135234046 has 4 divisors (see below), whose sum is σ = 198904702851072. Its totient is φ = 66301567617022.

The previous prime is 132603135234029. The next prime is 132603135234049. The reversal of 132603135234046 is 640432531306231.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 132603135233993 and 132603135234011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132603135234049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33150783808510 + ... + 33150783808513.

It is an arithmetic number, because the mean of its divisors is an integer number (49726175712768).

Almost surely, 2132603135234046 is an apocalyptic number.

132603135234046 is a deficient number, since it is larger than the sum of its proper divisors (66301567617026).

132603135234046 is an equidigital number, since it uses as much as digits as its factorization.

132603135234046 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66301567617025.

The product of its (nonzero) digits is 933120, while the sum is 43.

The spelling of 132603135234046 in words is "one hundred thirty-two trillion, six hundred three billion, one hundred thirty-five million, two hundred thirty-four thousand, forty-six".

Divisors: 1 2 66301567617023 132603135234046