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13264312555033 is a prime number
BaseRepresentation
bin1100000100000101011010…
…1000110101011000011001
31201222001111202012111212121
43001001112220311120121
53214310303003230113
644113312511541241
72536213013300011
oct301012650653031
951861452174777
1013264312555033
1142543aa701421
1215a286752a821
13752a8602b787
1433bdd3630c41
1518007dc72e8d
hexc1056a35619

13264312555033 has 2 divisors, whose sum is σ = 13264312555034. Its totient is φ = 13264312555032.

The previous prime is 13264312554973. The next prime is 13264312555051. The reversal of 13264312555033 is 33055521346231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12836763962649 + 427548592384 = 3582843^2 + 653872^2 .

It is a cyclic number.

It is not a de Polignac number, because 13264312555033 - 217 = 13264312423961 is a prime.

It is not a weakly prime, because it can be changed into another prime (13264312555063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6632156277516 + 6632156277517.

It is an arithmetic number, because the mean of its divisors is an integer number (6632156277517).

Almost surely, 213264312555033 is an apocalyptic number.

It is an amenable number.

13264312555033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13264312555033 is an equidigital number, since it uses as much as digits as its factorization.

13264312555033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972000, while the sum is 43.

The spelling of 13264312555033 in words is "thirteen trillion, two hundred sixty-four billion, three hundred twelve million, five hundred fifty-five thousand, thirty-three".