Base | Representation |
---|---|
bin | 11110001010010111001101… |
… | …100010100011000111111011 |
3 | 122101200112220102110122222011 |
4 | 132022113031202203013323 |
5 | 114341343343402314003 |
6 | 1150044103245310351 |
7 | 36640620502616521 |
oct | 3612271542430773 |
9 | 571615812418864 |
10 | 132653513323003 |
11 | 392a4048001192 |
12 | 12a651812653b7 |
13 | 590323236930a |
14 | 24a867008c311 |
15 | 105095042846d |
hex | 78a5cd8a31fb |
132653513323003 has 2 divisors, whose sum is σ = 132653513323004. Its totient is φ = 132653513323002.
The previous prime is 132653513322971. The next prime is 132653513323193. The reversal of 132653513323003 is 300323315356231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132653513323003 - 25 = 132653513322971 is a prime.
It is a super-2 number, since 2×1326535133230032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132153513323003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326756661501 + 66326756661502.
It is an arithmetic number, because the mean of its divisors is an integer number (66326756661502).
Almost surely, 2132653513323003 is an apocalyptic number.
132653513323003 is a deficient number, since it is larger than the sum of its proper divisors (1).
132653513323003 is an equidigital number, since it uses as much as digits as its factorization.
132653513323003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 437400, while the sum is 40.
Adding to 132653513323003 its reverse (300323315356231), we get a palindrome (432976828679234).
The spelling of 132653513323003 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred thirteen million, three hundred twenty-three thousand, three".
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