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132653664125107 is a prime number
BaseRepresentation
bin11110001010010111010110…
…100001110100000010110011
3122101200120021221020012120021
4132022113112201310002303
5114341344201004000412
61150044130233424311
736640624313460016
oct3612272641640263
9571616257205507
10132653664125107
11392a4115141024
1212a6520386b097
135903257689328
1424a868610537d
15105095d7b5607
hex78a5d68740b3

132653664125107 has 2 divisors, whose sum is σ = 132653664125108. Its totient is φ = 132653664125106.

The previous prime is 132653664124951. The next prime is 132653664125123. The reversal of 132653664125107 is 701521466356231.

It is a strong prime.

It is an emirp because it is prime and its reverse (701521466356231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132653664125107 is a prime.

It is a super-2 number, since 2×1326536641251072 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132653664125707) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326832062553 + 66326832062554.

It is an arithmetic number, because the mean of its divisors is an integer number (66326832062554).

Almost surely, 2132653664125107 is an apocalyptic number.

132653664125107 is a deficient number, since it is larger than the sum of its proper divisors (1).

132653664125107 is an equidigital number, since it uses as much as digits as its factorization.

132653664125107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5443200, while the sum is 52.

The spelling of 132653664125107 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, six hundred sixty-four million, one hundred twenty-five thousand, one hundred seven".