Base | Representation |
---|---|
bin | 11110001010010111101010… |
… | …110100100111110110000001 |
3 | 122101200121011122220010120122 |
4 | 132022113222310213312001 |
5 | 114341400400134201233 |
6 | 1150044224115150025 |
7 | 36640635616453526 |
oct | 3612275264476601 |
9 | 571617148803518 |
10 | 132654004600193 |
11 | 392a427a34aa9a |
12 | 12a652998a5315 |
13 | 59032b0088c8b |
14 | 24a86b941314d |
15 | 105097d61bd98 |
hex | 78a5ead27d81 |
132654004600193 has 2 divisors, whose sum is σ = 132654004600194. Its totient is φ = 132654004600192.
The previous prime is 132654004600099. The next prime is 132654004600261. The reversal of 132654004600193 is 391006400456231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125961497688049 + 6692506912144 = 11223257^2 + 2586988^2 .
It is a cyclic number.
It is not a de Polignac number, because 132654004600193 - 214 = 132654004583809 is a prime.
It is not a weakly prime, because it can be changed into another prime (132654004600093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327002300096 + 66327002300097.
It is an arithmetic number, because the mean of its divisors is an integer number (66327002300097).
Almost surely, 2132654004600193 is an apocalyptic number.
It is an amenable number.
132654004600193 is a deficient number, since it is larger than the sum of its proper divisors (1).
132654004600193 is an equidigital number, since it uses as much as digits as its factorization.
132654004600193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 44.
The spelling of 132654004600193 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, four million, six hundred thousand, one hundred ninety-three".
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