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132654144242041 is a prime number
BaseRepresentation
bin11110001010010111110011…
…001001010100000101111001
3122101200121112101122200011221
4132022113303021110011321
5114341401141411221131
61150044250024152041
736640642233422602
oct3612276311240571
9571617471580157
10132654144242041
11392a4341157a84
1212a65318608621
135903302c9c2a6
1424a86cdba2da9
15105098aa02411
hex78a5f3254179

132654144242041 has 2 divisors, whose sum is σ = 132654144242042. Its totient is φ = 132654144242040.

The previous prime is 132654144241943. The next prime is 132654144242051. The reversal of 132654144242041 is 140242441456231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76406829210000 + 56247315032041 = 8741100^2 + 7499821^2 .

It is a cyclic number.

It is not a de Polignac number, because 132654144242041 - 223 = 132654135853433 is a prime.

It is not a weakly prime, because it can be changed into another prime (132654144242051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327072121020 + 66327072121021.

It is an arithmetic number, because the mean of its divisors is an integer number (66327072121021).

Almost surely, 2132654144242041 is an apocalyptic number.

It is an amenable number.

132654144242041 is a deficient number, since it is larger than the sum of its proper divisors (1).

132654144242041 is an equidigital number, since it uses as much as digits as its factorization.

132654144242041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 737280, while the sum is 43.

Adding to 132654144242041 its reverse (140242441456231), we get a palindrome (272896585698272).

The spelling of 132654144242041 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, one hundred forty-four million, two hundred forty-two thousand, forty-one".