Base | Representation |
---|---|
bin | 11110001010010111110011… |
… | …010000000111011100000001 |
3 | 122101200121112112000021020111 |
4 | 132022113303100013130001 |
5 | 114341401142340301332 |
6 | 1150044250130311321 |
7 | 36640642254530425 |
oct | 3612276320073401 |
9 | 571617475007214 |
10 | 132654146025217 |
11 | 392a4342165783 |
12 | 12a65319128541 |
13 | 5903303474b1b |
14 | 24a86d0108b85 |
15 | 105098ac55947 |
hex | 78a5f3407701 |
132654146025217 has 2 divisors, whose sum is σ = 132654146025218. Its totient is φ = 132654146025216.
The previous prime is 132654146025211. The next prime is 132654146025239. The reversal of 132654146025217 is 712520641456231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 117788564065936 + 14865581959281 = 10853044^2 + 3855591^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132654146025217 is a prime.
It is not a weakly prime, because it can be changed into another prime (132654146025211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327073012608 + 66327073012609.
It is an arithmetic number, because the mean of its divisors is an integer number (66327073012609).
Almost surely, 2132654146025217 is an apocalyptic number.
It is an amenable number.
132654146025217 is a deficient number, since it is larger than the sum of its proper divisors (1).
132654146025217 is an equidigital number, since it uses as much as digits as its factorization.
132654146025217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 49.
The spelling of 132654146025217 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, one hundred forty-six million, twenty-five thousand, two hundred seventeen".
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