Base | Representation |
---|---|
bin | 11110001010011000101000… |
… | …000000011111101000010011 |
3 | 122101200200211012110212101112 |
4 | 132022120220000133220103 |
5 | 114341410000431404301 |
6 | 1150044514025123535 |
7 | 36641003222660015 |
oct | 3612305000375023 |
9 | 571620735425345 |
10 | 132655031122451 |
11 | 392a47568393a2 |
12 | 12a655256295ab |
13 | 59034149511b6 |
14 | 24a87758a61b5 |
15 | 10509dd7db9bb |
hex | 78a62801fa13 |
132655031122451 has 2 divisors, whose sum is σ = 132655031122452. Its totient is φ = 132655031122450.
The previous prime is 132655031122417. The next prime is 132655031122489. The reversal of 132655031122451 is 154221130556231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132655031122451 - 214 = 132655031106067 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132655031122399 and 132655031122408.
It is not a weakly prime, because it can be changed into another prime (132655030122451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327515561225 + 66327515561226.
It is an arithmetic number, because the mean of its divisors is an integer number (66327515561226).
Almost surely, 2132655031122451 is an apocalyptic number.
132655031122451 is a deficient number, since it is larger than the sum of its proper divisors (1).
132655031122451 is an equidigital number, since it uses as much as digits as its factorization.
132655031122451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 41.
Adding to 132655031122451 its reverse (154221130556231), we get a palindrome (286876161678682).
The spelling of 132655031122451 in words is "one hundred thirty-two trillion, six hundred fifty-five billion, thirty-one million, one hundred twenty-two thousand, four hundred fifty-one".
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