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13270645751 = 111206422341
BaseRepresentation
bin11000101101111110…
…11111101111110111
31021020212001122122012
430112333133233313
5204134241131001
610032455554435
7646600425206
oct142677375767
937225048565
1013270645751
11569aa2a630
1226a438ba1b
13133649270c
148dc69b23d
1552a0b32bb
hex316fdfbf7

13270645751 has 4 divisors (see below), whose sum is σ = 14477068104. Its totient is φ = 12064223400.

The previous prime is 13270645747. The next prime is 13270645771. The reversal of 13270645751 is 15754607231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13270645751 - 22 = 13270645747 is a prime.

It is a super-2 number, since 2×132706457512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13270645699 and 13270645708.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13270645711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 603211160 + ... + 603211181.

It is an arithmetic number, because the mean of its divisors is an integer number (3619267026).

Almost surely, 213270645751 is an apocalyptic number.

13270645751 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13270645751 is a deficient number, since it is larger than the sum of its proper divisors (1206422353).

13270645751 is a wasteful number, since it uses less digits than its factorization.

13270645751 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1206422352.

The product of its (nonzero) digits is 176400, while the sum is 41.

The spelling of 13270645751 in words is "thirteen billion, two hundred seventy million, six hundred forty-five thousand, seven hundred fifty-one".

Divisors: 1 11 1206422341 13270645751