Base | Representation |
---|---|
bin | 11000101101111110… |
… | …11111110000001011 |
3 | 1021020212001122122221 |
4 | 30112333133300023 |
5 | 204134241131041 |
6 | 10032455554511 |
7 | 646600425235 |
oct | 142677376013 |
9 | 37225048587 |
10 | 13270645771 |
11 | 569aa2a649 |
12 | 26a438ba37 |
13 | 1336492726 |
14 | 8dc69b255 |
15 | 52a0b32d1 |
hex | 316fdfc0b |
13270645771 has 2 divisors, whose sum is σ = 13270645772. Its totient is φ = 13270645770.
The previous prime is 13270645747. The next prime is 13270645783. The reversal of 13270645771 is 17754607231.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (17754607231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13270645771 - 29 = 13270645259 is a prime.
It is a super-2 number, since 2×132706457712 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13270645711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6635322885 + 6635322886.
It is an arithmetic number, because the mean of its divisors is an integer number (6635322886).
Almost surely, 213270645771 is an apocalyptic number.
13270645771 is a deficient number, since it is larger than the sum of its proper divisors (1).
13270645771 is an equidigital number, since it uses as much as digits as its factorization.
13270645771 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 246960, while the sum is 43.
The spelling of 13270645771 in words is "thirteen billion, two hundred seventy million, six hundred forty-five thousand, seven hundred seventy-one".
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