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13270672625701 = 131101302844471
BaseRepresentation
bin1100000100011101000110…
…1110100101000000100101
31201222122220222210120122111
43001013101232211000211
53214411314143010301
644120243550201021
72536526432065051
oct301072156450045
951878828716574
1013270672625701
114257073805677
1215a3b414b3171
1375355a8984ba
1433c4381acc61
151803022d3551
hexc11d1ba5025

13270672625701 has 4 divisors (see below), whose sum is σ = 13371975470304. Its totient is φ = 13169369781100.

The previous prime is 13270672625689. The next prime is 13270672625711. The reversal of 13270672625701 is 10752627607231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13270672625701 - 25 = 13270672625669 is a prime.

It is a super-2 number, since 2×132706726257012 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13270672625711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50651422105 + ... + 50651422366.

It is an arithmetic number, because the mean of its divisors is an integer number (3342993867576).

Almost surely, 213270672625701 is an apocalyptic number.

It is an amenable number.

13270672625701 is a deficient number, since it is larger than the sum of its proper divisors (101302844603).

13270672625701 is a wasteful number, since it uses less digits than its factorization.

13270672625701 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101302844602.

The product of its (nonzero) digits is 1481760, while the sum is 49.

The spelling of 13270672625701 in words is "thirteen trillion, two hundred seventy billion, six hundred seventy-two million, six hundred twenty-five thousand, seven hundred one".

Divisors: 1 131 101302844471 13270672625701