Base | Representation |
---|---|
bin | 10011010100000110100… |
… | …110111111101101111001 |
3 | 11200212212201220112202112 |
4 | 103110012212333231321 |
5 | 133221204434431332 |
6 | 2453422145342105 |
7 | 164614430662433 |
oct | 23240646775571 |
9 | 4625781815675 |
10 | 1327255780217 |
11 | 471982317294 |
12 | 195293337935 |
13 | 9820ca92643 |
14 | 4834d36d653 |
15 | 247d1b81db2 |
hex | 135069bfb79 |
1327255780217 has 2 divisors, whose sum is σ = 1327255780218. Its totient is φ = 1327255780216.
The previous prime is 1327255780211. The next prime is 1327255780273. The reversal of 1327255780217 is 7120875527231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1309871094016 + 17384686201 = 1144496^2 + 131851^2 .
It is a cyclic number.
It is not a de Polignac number, because 1327255780217 - 28 = 1327255779961 is a prime.
It is a super-2 number, since 2×13272557802172 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1327255780211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 663627890108 + 663627890109.
It is an arithmetic number, because the mean of its divisors is an integer number (663627890109).
Almost surely, 21327255780217 is an apocalyptic number.
It is an amenable number.
1327255780217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1327255780217 is an equidigital number, since it uses as much as digits as its factorization.
1327255780217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1646400, while the sum is 50.
The spelling of 1327255780217 in words is "one trillion, three hundred twenty-seven billion, two hundred fifty-five million, seven hundred eighty thousand, two hundred seventeen".
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