Base | Representation |
---|---|
bin | 11110001011101010111111… |
… | …011101101100110110010000 |
3 | 122102000011002202121202012001 |
4 | 132023222333131230312100 |
5 | 114344332112144444204 |
6 | 1150153301533043344 |
7 | 36650253653436412 |
oct | 3613527735546620 |
9 | 572004082552161 |
10 | 132743471484304 |
11 | 3932921004623a |
12 | 12a7a6a8026554 |
13 | 590b86a5ccb65 |
14 | 24acb655b89b2 |
15 | 1052e67c8d4a4 |
hex | 78babf76cd90 |
132743471484304 has 10 divisors (see below), whose sum is σ = 257190476000870. Its totient is φ = 66371735742144.
The previous prime is 132743471484301. The next prime is 132743471484313. The reversal of 132743471484304 is 403484174347231.
It can be written as a sum of positive squares in only one way, i.e., 127926324444304 + 4817147040000 = 11310452^2 + 2194800^2 .
It is not an unprimeable number, because it can be changed into a prime (132743471484301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4148233483869 + ... + 4148233483900.
It is an arithmetic number, because the mean of its divisors is an integer number (25719047600087).
Almost surely, 2132743471484304 is an apocalyptic number.
It is an amenable number.
132743471484304 is a deficient number, since it is larger than the sum of its proper divisors (124447004516566).
132743471484304 is an equidigital number, since it uses as much as digits as its factorization.
132743471484304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8296466967777 (or 8296466967771 counting only the distinct ones).
The product of its (nonzero) digits is 21676032, while the sum is 55.
The spelling of 132743471484304 in words is "one hundred thirty-two trillion, seven hundred forty-three billion, four hundred seventy-one million, four hundred eighty-four thousand, three hundred four".
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