Base | Representation |
---|---|
bin | 1100000100110111000010… |
… | …0100000110110111011001 |
3 | 1202000022220000220001000221 |
4 | 3001031300210012313121 |
5 | 3220020042400103213 |
6 | 44123354331000041 |
7 | 2540164052313265 |
oct | 301156044066731 |
9 | 52008800801027 |
10 | 13277632425433 |
11 | 425a0153a2182 |
12 | 15a5364299021 |
13 | 7540c97676ac |
14 | 33c8d86630a5 |
15 | 1805ad30b38d |
hex | c1370906dd9 |
13277632425433 has 2 divisors, whose sum is σ = 13277632425434. Its totient is φ = 13277632425432.
The previous prime is 13277632425419. The next prime is 13277632425487. The reversal of 13277632425433 is 33452423677231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13103907684624 + 173724740809 = 3619932^2 + 416803^2 .
It is a cyclic number.
It is not a de Polignac number, because 13277632425433 - 217 = 13277632294361 is a prime.
It is not a weakly prime, because it can be changed into another prime (13277632425413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6638816212716 + 6638816212717.
It is an arithmetic number, because the mean of its divisors is an integer number (6638816212717).
Almost surely, 213277632425433 is an apocalyptic number.
It is an amenable number.
13277632425433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13277632425433 is an equidigital number, since it uses as much as digits as its factorization.
13277632425433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15240960, while the sum is 52.
The spelling of 13277632425433 in words is "thirteen trillion, two hundred seventy-seven billion, six hundred thirty-two million, four hundred twenty-five thousand, four hundred thirty-three".
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