Base | Representation |
---|---|
bin | 111101110110111110… |
… | …1110001000111110001 |
3 | 110200212221112212211101 |
4 | 1323231331301013301 |
5 | 4134024400123212 |
6 | 141005420244401 |
7 | 12411635235415 |
oct | 1735575610761 |
9 | 420787485741 |
10 | 132841411057 |
11 | 51379571333 |
12 | 218b43a0701 |
13 | c6b0770954 |
14 | 66029ccd45 |
15 | 36c752d157 |
hex | 1eedf711f1 |
132841411057 has 2 divisors, whose sum is σ = 132841411058. Its totient is φ = 132841411056.
The previous prime is 132841411013. The next prime is 132841411069. The reversal of 132841411057 is 750114148231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87169019536 + 45672391521 = 295244^2 + 213711^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132841411057 is a prime.
It is a super-2 number, since 2×1328414110572 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132841411007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66420705528 + 66420705529.
It is an arithmetic number, because the mean of its divisors is an integer number (66420705529).
Almost surely, 2132841411057 is an apocalyptic number.
It is an amenable number.
132841411057 is a deficient number, since it is larger than the sum of its proper divisors (1).
132841411057 is an equidigital number, since it uses as much as digits as its factorization.
132841411057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 37.
Adding to 132841411057 its reverse (750114148231), we get a palindrome (882955559288).
The spelling of 132841411057 in words is "one hundred thirty-two billion, eight hundred forty-one million, four hundred eleven thousand, fifty-seven".
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