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132860732135041 is a prime number
BaseRepresentation
bin11110001101011000001100…
…101111100101011010000001
3122102102100202212012222221101
4132031120030233211122001
5114403242234411310131
61150323213331454401
736661604540511001
oct3615301457453201
9572370685188841
10132860732135041
1139373a13688749
1212a99372457401
1359199371041b1
1424b46caba8001
15105602c4d9c61
hex78d60cbe5681

132860732135041 has 2 divisors, whose sum is σ = 132860732135042. Its totient is φ = 132860732135040.

The previous prime is 132860732135023. The next prime is 132860732135057. The reversal of 132860732135041 is 140531237068231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99598982845041 + 33261749290000 = 9979929^2 + 5767300^2 .

It is a cyclic number.

It is not a de Polignac number, because 132860732135041 - 25 = 132860732135009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132860732134982 and 132860732135000.

It is not a weakly prime, because it can be changed into another prime (132860732135081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66430366067520 + 66430366067521.

It is an arithmetic number, because the mean of its divisors is an integer number (66430366067521).

Almost surely, 2132860732135041 is an apocalyptic number.

It is an amenable number.

132860732135041 is a deficient number, since it is larger than the sum of its proper divisors (1).

132860732135041 is an equidigital number, since it uses as much as digits as its factorization.

132860732135041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 725760, while the sum is 46.

The spelling of 132860732135041 in words is "one hundred thirty-two trillion, eight hundred sixty billion, seven hundred thirty-two million, one hundred thirty-five thousand, forty-one".