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132943960661401 is a prime number
BaseRepresentation
bin11110001110100101101101…
…100011001101110110011001
3122102201022121012101012111201
4132032211231203031312121
5114411123212412131101
61150425340135554201
740000612164352621
oct3616455543156631
9572638535335451
10132943960661401
11393a6242a5142a
1212ab151b52b961
13592473c084b26
1424b8744635881
15105829e13de01
hex78e96d8cdd99

132943960661401 has 2 divisors, whose sum is σ = 132943960661402. Its totient is φ = 132943960661400.

The previous prime is 132943960661371. The next prime is 132943960661453. The reversal of 132943960661401 is 104166069349231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130168817814025 + 2775142847376 = 11409155^2 + 1665876^2 .

It is a cyclic number.

It is not a de Polignac number, because 132943960661401 - 27 = 132943960661273 is a prime.

It is a super-2 number, since 2×1329439606614012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132943960661201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66471980330700 + 66471980330701.

It is an arithmetic number, because the mean of its divisors is an integer number (66471980330701).

Almost surely, 2132943960661401 is an apocalyptic number.

It is an amenable number.

132943960661401 is a deficient number, since it is larger than the sum of its proper divisors (1).

132943960661401 is an equidigital number, since it uses as much as digits as its factorization.

132943960661401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5038848, while the sum is 55.

The spelling of 132943960661401 in words is "one hundred thirty-two trillion, nine hundred forty-three billion, nine hundred sixty million, six hundred sixty-one thousand, four hundred one".