Base | Representation |
---|---|
bin | 11110001110100101101101… |
… | …100011001101110110011001 |
3 | 122102201022121012101012111201 |
4 | 132032211231203031312121 |
5 | 114411123212412131101 |
6 | 1150425340135554201 |
7 | 40000612164352621 |
oct | 3616455543156631 |
9 | 572638535335451 |
10 | 132943960661401 |
11 | 393a6242a5142a |
12 | 12ab151b52b961 |
13 | 592473c084b26 |
14 | 24b8744635881 |
15 | 105829e13de01 |
hex | 78e96d8cdd99 |
132943960661401 has 2 divisors, whose sum is σ = 132943960661402. Its totient is φ = 132943960661400.
The previous prime is 132943960661371. The next prime is 132943960661453. The reversal of 132943960661401 is 104166069349231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130168817814025 + 2775142847376 = 11409155^2 + 1665876^2 .
It is a cyclic number.
It is not a de Polignac number, because 132943960661401 - 27 = 132943960661273 is a prime.
It is a super-2 number, since 2×1329439606614012 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132943960661201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66471980330700 + 66471980330701.
It is an arithmetic number, because the mean of its divisors is an integer number (66471980330701).
Almost surely, 2132943960661401 is an apocalyptic number.
It is an amenable number.
132943960661401 is a deficient number, since it is larger than the sum of its proper divisors (1).
132943960661401 is an equidigital number, since it uses as much as digits as its factorization.
132943960661401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5038848, while the sum is 55.
The spelling of 132943960661401 in words is "one hundred thirty-two trillion, nine hundred forty-three billion, nine hundred sixty million, six hundred sixty-one thousand, four hundred one".
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