Base | Representation |
---|---|
bin | 10011010110011010110… |
… | …101110101101001001001 |
3 | 11201010022001111010002121 |
4 | 103112122311311221021 |
5 | 133241303112332311 |
6 | 2454513024531241 |
7 | 165033156306646 |
oct | 23263265655111 |
9 | 4633261433077 |
10 | 1329742699081 |
11 | 472a390a6235 |
12 | 195868180b21 |
13 | 98518091974 |
14 | 48507776dcd |
15 | 248ca176b71 |
hex | 1359ad75a49 |
1329742699081 has 2 divisors, whose sum is σ = 1329742699082. Its totient is φ = 1329742699080.
The previous prime is 1329742699063. The next prime is 1329742699123. The reversal of 1329742699081 is 1809962479231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1033272250000 + 296470449081 = 1016500^2 + 544491^2 .
It is an emirp because it is prime and its reverse (1809962479231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1329742699081 - 27 = 1329742698953 is a prime.
It is a super-2 number, since 2×13297426990812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1329742699781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 664871349540 + 664871349541.
It is an arithmetic number, because the mean of its divisors is an integer number (664871349541).
Almost surely, 21329742699081 is an apocalyptic number.
It is an amenable number.
1329742699081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1329742699081 is an equidigital number, since it uses as much as digits as its factorization.
1329742699081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11757312, while the sum is 61.
The spelling of 1329742699081 in words is "one trillion, three hundred twenty-nine billion, seven hundred forty-two million, six hundred ninety-nine thousand, eighty-one".
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